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4x^2+12=3x^2
We move all terms to the left:
4x^2+12-(3x^2)=0
We add all the numbers together, and all the variables
x^2+12=0
a = 1; b = 0; c = +12;
Δ = b2-4ac
Δ = 02-4·1·12
Δ = -48
Delta is less than zero, so there is no solution for the equation
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